- Octagon side
- 4
- Prism length
- 10
772.548340
Open with these values772.548340units³
Result: 772.548340 units³A regular octagon of side a covers 2(1 + √2) × a², about 4.828 × a² — nearly five squares of the side. Multiply by the length for the volume: side 4, length 10 gives 320(1 + √2), about 772.5 cubic units. Enter one edge, not the width across the flats.
Held fixed: Octagon side 4.000.
| Prism length | Result |
|---|---|
| 2.500 | 193.137085 |
| 5.000 | 386.274170 |
| 7.500 | 579.411255 |
| 10.000Your value | 772.548340 |
| 12.500 | 965.685425 |
| 15.000 | 1,158.822510 |
| 17.500 | 1,351.959595 |
| 20.000 | 1,545.096680 |
772.548340
Open with these values4.828427
Open with these values1,207.106781
Open with these valuesV = 2(1 + √2) × a² × L
| Side, length | Exact | Volume |
|---|---|---|
| 0.5, 3 | 3(1 + √2) ÷ 2 | 3.621320 |
| 1, 1 | 2(1 + √2) | 4.828427 |
| 2, 6 | 48(1 + √2) | 115.882251 |
| 4, 10 | 320(1 + √2) | 772.548340 |
| 5, 10 | 500(1 + √2) | 1207.106781 |
Find the area of the octagonal end, 2(1 + √2) × a², then multiply by the prism length. The area factor is about 4.828427, so a side of 4 and a length of 10 give 77.254834 × 10 = 772.548340 cubic units.
A regular octagon with side a has area 2(1 + √2) × a², about 4.828427 × a². For a side of 4 that is 77.254834 square units, and that cross-section stays the same all the way along the prism.
The side, meaning one of the eight equal edges. The width across the flats is (1 + √2) times the side, about 2.414 times, so divide by that before entering.
A prism is its cross-section swept along a straight line, so its volume is always cross-section area times length. That holds for any prism — octagonal, hexagonal or rectangular. Doubling the length doubles the volume while the cross-section stays put.
Whatever you entered, cubed. Side and length in centimetres give cubic centimetres, in inches cubic inches. Both inputs must use the same unit.
Information, not professional advice.
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