- Hexagon side
- 4
- Prism length
- 10
415.692194
Open with these values415.692194units³
Result: 415.692194 units³A regular hexagon of side a covers 3√3/2 × a², about 2.598 × a². Multiply that by the length and you have the volume: a hex bar of side 4 and length 10 holds 240√3, roughly 415.7 cubic units. Enter the side, not the width across the flats — that one is √3 times longer.
Held fixed: Hexagon side 4.000.
| Prism length | Result |
|---|---|
| 2.500 | 103.923048 |
| 5.000 | 207.846097 |
| 7.500 | 311.769145 |
| 10.000Your value | 415.692194 |
| 12.500 | 519.615242 |
| 15.000 | 623.538291 |
| 17.500 | 727.461339 |
| 20.000 | 831.384388 |
415.692194
Open with these values2.598076
Open with these values51.961524
Open with these valuesV = (3√3 ÷ 2) × a² × L
| Side, length | Exact | Volume |
|---|---|---|
| 0.5, 3 | 9√3 ÷ 8 | 1.948557 |
| 1, 1 | 3√3 ÷ 2 | 2.598076 |
| 2, 5 | 30√3 | 51.961524 |
| 3, 8 | 108√3 | 187.061487 |
| 4, 10 | 240√3 | 415.692194 |
Find the area of the hexagonal end — (3√3/2) × a², about 2.598 × a² — then multiply by the prism length. For a side of 4 and a length of 10 that is 41.569219 × 10 = 415.692194 cubic units.
The side, meaning one of the six equal edges. The width across the flats is √3 times the side and the width across the corners is exactly twice it, so divide by 1.732051 or by 2 before entering.
A regular hexagon is six equilateral triangles meeting at the centre. Each has area (√3/4) × a², and six of them give (3√3/2) × a². That cross-section is the same at every slice along the prism.
No. The formula assumes a regular hexagon — all six sides equal, every angle 120° — swept straight along the length. A tapered or twisted bar needs a different calculation.
Whatever you entered, cubed. Side and length in centimetres give cubic centimetres, in inches cubic inches. Both inputs must use the same unit.
Information, not professional advice.
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