- Time falling
- 1s
4.903m
Open with these values44.130m
Result: 44.130 mA dropped object covers ½ × g × t², so after three seconds it has fallen 44.13 m. The distance grows with the square of the time: the third second alone accounts for more than the first two together. Air resistance is ignored, so this is the vacuum value and an upper bound.
4.903m
Open with these values44.130m
Open with these values122.583m
Open with these valuesd = ½ × g × t²
After one second the drop is 4.903 m and after two it is 19.613 m, but after three it is 44.130 m. The third second alone therefore adds 24.517 m, more than the first two put together.
Standard gravity is a conventional value listed as exact by NIST, which is why one second of falling gives exactly half of it: 4.903325 m. Local gravity varies slightly with latitude and altitude, and on the Moon it is only about 1.62 m/s².
The formula contains no shape and no density, only time, so a feather and a lead ball both reach 44.130 m after three seconds. In real air the feather is left behind almost immediately.
A belly-down skydiver stops accelerating at roughly 55 m/s, which v = g × t reaches after about 5.6 seconds. Beyond that the calculator keeps speeding the fall up while the real one no longer does, so long drops through air come out far too deep.
Heavier objects fall faster, so a bowling ball beats a tennis ball.
With air resistance ignored the mass drops out of the formula entirely and both cover 44.130 m in three seconds. Drag separates them in real air, not weight.
Three times the falling time means three times the distance.
It means nine times the distance, because the time is squared: 4.903 m after one second becomes 44.130 m after three.
Reading 44.130 as the speed reached after three seconds.
That is the distance in metres, measured from the release point. The speed at that moment is g × t = 29.42 m/s, about 106 km/h.
| Time (s) | Speed reached (m/s) | Distance fallen (m) |
|---|---|---|
| 0 | 0.00 | 0.000 |
| 1 | 9.81 | 4.903 |
| 2 | 19.61 | 19.613 |
| 3 | 29.42 | 44.130 |
| 5 | 49.03 | 122.583 |
| 10 | 98.07 | 490.332 |
Free fall is motion under gravity alone, with air resistance ignored. The distance an object drops after a time t is d = ½ × g × t², where g is the acceleration due to gravity. With g = 9.80665 m/s², an object falling for 3 seconds covers 44.129925 m.
That is standard gravity, the conventional value fixed by international agreement and listed as exact by NIST. It means a falling object gains about 9.81 m/s of speed every second. Local gravity varies slightly with latitude and altitude, and on the Moon g is only about 1.62 m/s².
The speed is not the output here, but it follows from the same g: v = g × t. After 3 seconds that is 29.41995 m/s, about 106 km/h. Distance grows with the square of time while speed grows in a straight line.
No — it computes idealised free fall in a vacuum. In real air, drag grows with speed until it balances gravity and the object stops accelerating at its terminal velocity, roughly 55 m/s for a belly-down skydiver. For short drops or dense objects the difference is small.
It predicts how long a dropped object takes to reach the ground and how fast it arrives, which is the basis of drop-tower rides, construction safety rules, and ballistics. Turned around, it also gives the height of a cliff or a well from the time a stone takes to fall.
Information, not professional advice.
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