- Semi-major axis a
- 5
- Semi-minor axis b
- 3
0.800000
Open with these values0.800000
Result: 0.800000Eccentricity says how far an ellipse is from being a circle: e = √(a² − b²) ÷ a, a pure ratio between 0 and 1. Zero is a circle, values near one are long and thin. Both axes go in with the same length unit; the ratio itself has no unit.
Held fixed: Semi-major axis a 5.000.
| Semi-minor axis b | Result |
|---|---|
| 1.000 | 0.979796 |
| 2.000 | 0.916515 |
| 3.000Your value | 0.800000 |
| 4.000 | 0.600000 |
| 5.000 | 0.000000 |
| 6.000 | 0.552771 |
0.800000
Open with these values0.923077
Open with these values0.000000
Open with these valuese = √(a² − b²) ÷ a
| a, b | Exact | Eccentricity |
|---|---|---|
| 5, 5 | 0 | 0.000000 |
| 5, 4 | 3/5 | 0.600000 |
| 5, 3 | 4/5 | 0.800000 |
| 10, 6 | 4/5 | 0.800000 |
| 2, 1 | √3/2 | 0.866025 |
| 13, 5 | 12/13 | 0.923077 |
Subtract the squared minor axis from the squared major axis, take the square root and divide by the major axis. With a = 5 and b = 3 that is 4/5, exactly 0.8.
The two axes are equal, so the ellipse is a circle. The foci sit on top of each other in the centre.
No. The calculator takes the larger of the two as the major axis, so a swapped pair describes the same ellipse and gives the same answer.
At a distance of c = √(a² − b²) from the centre, on the long axis. With a = 5 and b = 3 that is 4, so the foci are 8 apart.
None. Eccentricity is a ratio of two lengths, so the units cancel out — as long as both axes use the same one.
Information, not professional advice.
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