- Primary voltage Vp (V)
- 120V
- Primary turns Np
- 100
- Secondary turns Ns
- 10
12.000V
Open with these values12.000V
Result: 12.000 VVoltage follows the turns in direct proportion: Vs = Vp × Ns ÷ Np. Only the ratio matters — 100:10 and 1000:100 both step down 10:1. Current goes the other way: Vp × Ip = Vs × Is, so a tenfold voltage drop buys roughly ten times the secondary current.
Held fixed: Primary voltage Vp (V) 120.000 V, Primary turns Np 100.
| Secondary turns Ns | Result (V) |
|---|---|
| 3 | 3.000 |
| 5 | 6.000 |
| 8 | 9.000 |
| 10Your value | 12.000 |
| 13 | 15.000 |
| 15 | 18.000 |
| 18 | 21.000 |
| 20 | 24.000 |
12.000V
Open with these values11.500V
Open with these values1,200.000V
Open with these valuesVs = Vp × Ns ÷ Np
| Vp, Np, Ns | What it does | Vs |
|---|---|---|
| 120, 100, 10 | 10:1 step-down | 12 |
| 120, 10, 100 | 1:10 step-up | 1200 |
| 240, 100, 100 | 1:1 isolation | 240 |
| 12, 2, 1 | 2:1 step-down | 6 |
| 230, 1000, 50 | 20:1 step-down | 11.5 |
Multiply the primary voltage by the turns ratio Ns ÷ Np. For 120 V with 100 primary and 10 secondary turns that is 120 × 0.1 = 12 V. The voltage scales in direct proportion to the turns.
More secondary turns than primary steps the voltage up; fewer steps it down. With equal turns the voltage is unchanged — an isolation transformer.
Only the ratio Ns ÷ Np sets the voltage: 100:10 and 1000:100 both give the same 10:1 step-down. Absolute counts affect core size, magnetising current and frequency response instead.
Power is conserved in an ideal transformer, so current changes inversely to voltage: Ip × Vp = Is × Vs. Stepping voltage down by ten raises the available secondary current by about ten.
Yes. The formula assumes perfect magnetic coupling and no winding resistance, leakage or core losses. Real transformers run a few percent lower under load.
Information, not professional advice.
Diese Seite gibt es auch auf Deutsch.
Zu Deutsch wechseln