- Mole fraction x (0 to 1)
- 0.21
- Total pressure (kPa)
- 101.325kPa
21.278kPa
Open with these values21.278kPa
Result: 21.278 kPaDalton's law: a gas contributes its mole fraction of the total pressure. Oxygen at a mole fraction of 0.21 in air at 101.325 kPa has a partial pressure of 21.278 kPa. The mole fraction has no unit, so the answer comes back in whatever pressure unit you entered.
Held fixed: Mole fraction x (0 to 1) 0.2100.
| Total pressure (kPa) (kPa) | Result (kPa) |
|---|---|
| 0.000 | 0.000 |
| 50.000 | 10.500 |
| 100.000 | 21.000 |
| 101.325Your value | 21.278 |
| 150.000 | 31.500 |
| 200.000 | 42.000 |
21.278kPa
Open with these values79.034kPa
Open with these values100.000kPa
Open with these valuesP_i = x × P_total
| Mole fraction, total pressure | The gas | Partial pressure in kPa |
|---|---|---|
| 0, 101.325 | a gas that is not in the mixture | 0.000 |
| 0.21, 101.325 | oxygen in dry air at sea level | 21.278 |
| 0.78, 101.325 | nitrogen in dry air at sea level | 79.034 |
| 0.5, 200 | half of a mixture at 200 kPa | 100.000 |
| 1, 101.325 | a pure gas — the whole pressure | 101.325 |
Multiply the mole fraction of the gas by the total pressure of the mixture: P_i = x × P_total. Oxygen at x = 0.21 in air at 101.325 kPa gives 21.278 kPa.
The total pressure of a mixture of non-reacting gases is the sum of the pressures each gas would exert alone. That is the same as saying every gas takes its mole fraction of the total, so all the partial pressures add back up to it.
The moles of that one gas divided by the total moles of all gases, a number between 0 and 1. Dry air is about 0.78 nitrogen and 0.21 oxygen.
The one you entered, because the mole fraction is dimensionless. Standard atmospheric pressure is 101.325 kPa, which is 1 atm or 760 mmHg.
Information, not professional advice.
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