- Mass (kg)
- 2kg
- Distance from the axis (m)
- 0.5m
0.50000kg·m²
Open with these values0.50000kg·m²
Result: 0.50000 kg·m²This is the point-mass case, I = m × r², with no shape factor in front: 2 kg at 0.5 m from the axis gives 0.5 kg·m². The same formula holds for a thin ring spinning about its own axis. A solid disc is half of this, a solid sphere two fifths — use those factors when the mass is spread out.
0.50000kg·m²
Open with these values20.00000kg·m²
Open with these values62.50000kg·m²
Open with these valuesI = m × r²
| Mass, distance | Example | Moment of inertia |
|---|---|---|
| 0.145, 0.3 | A baseball held 30 cm out | 0.01305 |
| 2, 0.5 | A 2 kg mass on a 50 cm arm | 0.5 |
| 1, 1 | The unit case | 1 |
| 5, 2 | A 5 kg weight two metres out | 20 |
| 1000, 0.25 | A one-tonne flywheel rim | 62.5 |
For a point mass, multiply the mass by the square of its distance from the axis: I = m × r². Kilograms and metres give kg·m². A 2 kg mass 0.5 m from the axis has 0.5 kg·m².
Not as it stands — those bodies carry a shape factor. A solid disc or cylinder is ½mr², a solid sphere ⅖mr², a rod about its centre 1/12 mL², and a thin ring mr². Take the number from this calculator and multiply it by the factor for your shape.
Because the distance from the axis enters the definition squared. Doubling the radius multiplies the moment of inertia by four, which is why mass far from the axis matters much more than the same mass close to it.
Mass measures resistance to a change in straight-line motion; the moment of inertia measures resistance to a change in rotation. Mass depends only on the object, but the moment of inertia also depends on where the axis is.
Then add m × d² to the centre-of-mass value, where d is the distance between the two parallel axes. That is the parallel axis theorem, and it has its own calculator.
Information, not professional advice.
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