- Battery capacity
- 3000mAh
- Current draw
- 200mA
15.00h
Open with these values15.00h
Result: 15.00 hCapacity divided by draw: 3,000 mAh at 200 mA runs 15 hours, because mAh ÷ mA leaves hours. Treat it as the ceiling, not the promise — voltage sags under load, converters lose a little, and a heavy draw lowers the usable capacity by a further 10 to 20 %.
15.00h
Open with these values10.00h
Open with these values12.50h
Open with these valueshours = capacity (mAh) ÷ draw (mA)
| Capacity, draw | Typical device | Runtime (h) |
|---|---|---|
| 1500, 300 | Wireless headset | 5.00 |
| 2000, 250 | Fitness tracker charge | 8.00 |
| 3000, 200 | Phone on standby | 15.00 |
| 5000, 500 | Tablet, light use | 10.00 |
| 10000, 800 | Power bank feeding a router | 12.50 |
Divide the capacity in mAh by the average draw in mA. 3,000 mAh at 200 mA gives 15 hours, since the milliamps cancel and hours remain.
The formula assumes the full capacity is usable at a steady current. In practice the cell ages, the voltage drops before it is empty, and higher draws lose extra capacity through internal resistance.
No — expect about 1.5 charges. The bank steps its cell voltage up to 5 V and back down again, and each conversion costs 10 to 20 %.
Use the average draw over a full duty cycle. For a sensor that wakes briefly every minute, that average can be a small fraction of its peak current.
Information, not professional advice.
Diese Seite gibt es auch auf Deutsch.
Zu Deutsch wechseln