- Inner radius
- 3
- Outer radius
- 5
- Angle
- 90°
12.566371
Open with these values12.566371units²
Result: 12.566371 units²An annular sector is a slice of a ring: the full annulus π(R² − r²) kept in the proportion θ ÷ 360. Both radii go in with the same length unit and the area comes back squared in that unit. A washer cut open, a lane of a curved running track.
Held fixed: Inner radius 3.000, Outer radius 5.000.
| Angle (°) | Result |
|---|---|
| 0.00 | 0.000000 |
| 25.00 | 3.490659 |
| 50.00 | 6.981317 |
| 75.00 | 10.471976 |
| 90.00Your value | 12.566371 |
| 100.00 | 13.962634 |
| 125.00 | 17.453293 |
| 150.00 | 20.943951 |
| 175.00 | 24.434610 |
12.566371
Open with these values6.283185
Open with these values155.508836
Open with these valuesA = π × (R² − r²) × θ ÷ 360
| Inner, outer, angle | Exact | Area |
|---|---|---|
| 2, 4, 60 | 2π | 6.283185 |
| 3, 5, 90 | 4π | 12.566371 |
| 4, 7, 120 | 11π | 34.557519 |
| 3, 5, 360 | 16π | 50.265482 |
| 1, 10, 180 | 49.5π | 155.508836 |
Square both radii, subtract the inner from the outer, multiply by π, then keep the fraction θ ÷ 360. From 3 to 5 over 90° gives 4π, about 12.57 square units.
The fraction becomes one and the result is the whole annulus, π(R² − r²). From 3 to 5 that is 16π, about 50.27.
Only when the inner radius is zero. Otherwise the hole in the middle is cut away and the piece is smaller.
The square of whatever you entered. Both radii must use the same length unit; the angle is always in degrees.
Information, not professional advice.
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